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Championship Manager 01/02

The following is a list of patched file extensions for this file type. Ext\Cm0102\*.DMGChampionship Manager 01/02.zip
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Created by Demomen, Team WCN Software.Q:

Quadratic Functions Question

The question asks for the graph of $f(x) = x^2+4x$ and what is the largest value of $x$ such that $f'(x)=1$
My solution
Solving for $f'(x)$ and equating it to $1$ we get $x^2+4x-2x = 1$ (using quadratic formula)
hence $x = \sqrt{2}$
I think my solution is wrong.
I tried using Maclaurin series and setting $f(x) = \sum_0^\infty c_nx^n$ and equating $f'(x) = 1$ we get
$1 = c_1x$ which yields $c_1 = 1$ hence $f(x)=x^2+4x$
But $f(2)=6$ which violates the domain of $f(x)$.
Could someone let me know if I’m on the right track?

Let $g(x)=x^2+4x$ and let $f(x)$ be the restriction of $g$ to the interval $[0,2]$. We want to find the largest $x$ such that $g(x

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