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. My antivirus related to the. I had the
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However, I just need to put it
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GPL+[0-9]*[0-9]*[0-9]*[0-9]*. win greg 0 64 0 25.13 win ce 1 64 0 [0-9]* [0-9]*.Q:
Retrieving information from a second query which is not listed in the first query
I’ve got a query where I get the top 50 users who have more than 1 comment made for them in the database.
So I’m using this query to do that:
SELECT
UUID as `user_id`,
(SELECT COUNT(*) FROM comments WHERE commentable = 1) as num_comments,
(SELECT COUNT(*) FROM comments WHERE commentable = 2) as num_comments_2
FROM
users WHERE num_comments > 1
ORDER BY num_comments_2 DESC
LIMIT 50;
Which works perfectly to get the top 50 users. What I also want to do is get the username who commented on the first instance of their UUID.
So I’ve tried using this
SELECT
user_id, username
FROM (
SELECT
UUID as `user_id`,
(SELECT COUNT(*) FROM comments WHERE commentable = 1) as num_comments,
(SELECT COUNT(*) FROM comments WHERE commentable = 2) as num_comments_2,
“the username who commented on the first instance of the UUID” as `username`
FROM
users WHERE num_comments > 1
ORDER BY num_comments_2 DESC
LIMIT 50
) as A
However, it fails stating that I have a subquery which requires more than 1 row
So how can I still use the same query to get all the data I want while not having it complain about me using a subquery for a column.
A:
You can replace this from subqueries to JOINs:
SELECT
UUID as `user_id`,
(SELECT COUNT(*) FROM comments WHERE commentable = 1) as num_comments,
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