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Specific implementation of the universal row-isomorphism $\psi$

The universal row-isomorphism $\psi$ is constructed as follows:
$$
\psi_{ij} = \sum_k \epsilon_{ijk} \theta_{ik} \text{ where } \epsilon_{ijk} = (-1)^{\eta_i \eta_j \eta_k} \text{ and } \eta_i = i-1.
$$
In Wikipedia, we read:

The elements $\psi_{ij}$ are normal, though of course not invertible. It is not difficult to see that $\psi \circ \sigma = \sigma \circ \psi$ for any permutation $\sigma$, and that if $\sigma$ is an automorphism then $\psi \circ \sigma$ is again an automorphism.

It is not difficult to see that $\psi \circ \sigma = \sigma \circ \psi$. But I don’t understand why this is the case for any permutation. I tried to find an element of the form $v_{i_1} \otimes \cdots \otimes v_{i_n} \otimes v_k$ in the column-space of $\psi$ but I can

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